Simply Supported Beam Calculator

Find the maximum bending moment, support reactions and deflection of a simply supported beam in seconds. Enter the span, load and section, and the result is checked live against the FERS finite-element solver — so you can see the closed-form answer and the FE answer agree.

Bending moment, reactions and deflection are all free, with no sign-up. A free account adds the downloadable HTML and PDF report.

Beam

E = 210.0 GPa

I = 3,893 cm⁴ · W_el = 324.4 cm³ · A = 39.13 cm²

Bending axis

Loads

Positions from end A · downward loads and clockwise moments are positive
  • 1. Point load

Results

Reaction at A, R_A
5.00 kN↑
Reaction at B, R_B
5.00 kN↑
Maximum shear |V|
5.00 kNat x = 0 m
Maximum sagging moment
15.0 kN·mat x = 3.00 m
Maximum deflection δ_max
5.50 mmL/1,090 · at x = 3.00 m
Rotation at A, θ_A
0.00275 rad0.158°
Rotation at B, θ_B
-0.00275 rad-0.158°
Max bending stress σ = M/W
46.2 MPaσ/f_y = 0.197
Plastic moment M_pl = W_pl·f_y
86.2 kN·mM/M_pl = 0.174
W_el needed for σ ≤ f_y
≥ 63.8 cm³

Euler–Bernoulli beam theory: linear elastic, small deflections, shear deformation neglected. Lateral-torsional buckling, local buckling and connections are not checked. σ/f_y is an elastic stress ratio, not a design check. Check a steel beam to Eurocode 3 →

Checked by the FERS finite-element solver

✓ matches the closed form
QuantityClosed formFERS FEDifference
Reaction at A5.000 kN5.000 kN< 0.0001 %
Reaction at B5.000 kN5.000 kN< 0.0001 %
Rotation at A0.002752 rad0.002752 rad< 0.0001 %
Rotation at B-0.002752 rad-0.002752 rad< 0.0001 %
Maximum deflection5.504 mm5.504 mm< 0.0001 %
Moment, worst FE station12.00 kN·m12.00 kN·m< 0.0001 %
Shear, worst FE station5.000 kN5.000 kN< 0.0001 %
Deflection, worst FE station5.425 mm5.425 mm< 0.0001 %

Precomputed with FERS 0.2.68 for this example; edit any input to re-run it live in your browser.

Downloadevery station, all four diagrams

Lighter sections that meet your limits

Screens a family of catalogue sections against your deflection limit and σ ≤ f_y, each with its own self-weight, and lists the lightest that meet both.

Diagrams

P = 10 kN @ 3 mR_A = 5 kNR_B = 5 kNL = 6 m
Draw moments
Bending moment M (kN·m) · sagging positive
0100246 mM = 15.0 kN·m

Hover or tap a diagram — or type x — to read every value at that point.

Step-by-step solution

Macaulay's method: one bending-moment expression for the whole span, integrated twice; the support conditions give the reactions and the integration constants. Hand-calculation units: N and mm, x in mm.

Bending stiffness

EI
EI = E × I = 210,000 N/mm² × 3.893×10⁷ mm⁴ = 8.175×10¹² N·mm²

Bending moment, slope and deflection

M(x) = R_A·x − 10,000·⟨x − 3,000⟩
EI·θ(x) = R_A·x²/2 − 10,000·⟨x − 3,000⟩²/2 + C₁
EI·v(x) = R_A·x³/6 − 10,000·⟨x − 3,000⟩³/6 + C₁·x + C₂

Support conditions

v(0) = 0 ⇒ C₂ = 0
M(0) = 0 ⇒ M_A = 0
v(6,000) = 0
M(6,000) = 0

Solving them

R_A
5,000 N
C₁
-2.25×10¹⁰ N·mm²
C₂
0 N·mm³
Equilibrium
R_B = −ΣF − R_A = 10,000 N − 5,000 N = 5,000 N

Peaks along the span

Maximum sagging moment
V(x̄) = 0 ⇒ x̄ = 3.00 m → M(x̄) = 15.0 kN·m
Maximum deflection
θ(x̄) = 0 ⇒ x̄ = 3.00 m → δ_max = |EI·v(x̄)| / EI = 4.5×10¹³ N·mm³ / 8.175×10¹² N·mm² = 5.50 mm
Bending stress
σ = M_max / W_el = 1.5×10⁷ N·mm / 324,420 mm³ = 46.2 MPa
Stress ratio
σ / f_y = 46.2 MPa / 235 MPa = 0.197
Span / deflection
L / δ_max = 6,000 mm / 5.504 mm = L/1,090

Formulas used

A simply supported beam has a pin at one end and a roller at the other. For the two most common load cases the maximum bending moment, support reaction and maximum deflection are:

Load caseMax momentReactionMax deflection
Central point load PM_max = P·L / 4R = P / 2δ_max = P·L³ / (48·E·I)
Uniformly distributed load wM_max = w·L² / 8R = w·L / 2δ_max = 5·w·L⁴ / (384·E·I)

where L is the span, P a point load, w a distributed load, E Young's modulus and I the second moment of area. The calculator above runs the FERS finite-element solver on your inputs and shows the analytical and finite-element answers agreeing live.

Worked example

Worked example: a 6 m simply supported IPE 240 steel beam (I = 3.89×10⁻⁵ m⁴, E = 210 GPa) with a 10 kN point load at midspan.

P15 kNm
Maximum bending moment, P·L/4
15.0 kNm
Reaction at each support, P/2
5.0 kN
Midspan deflection, P·L³/48EI
5.5 mm (≈ L/1090)

Frequently asked questions

Is this beam calculator free?

Yes. It runs entirely in your browser with no installation and no sign-up. Bending moments, reactions and deflections are all free; a free account adds the downloadable report (HTML and PDF).

How accurate is it?

Every result is computed two ways: from the closed-form beam equations and, live, by the FERS finite-element solver. You can watch the bending moment and reactions from the two methods agree on screen as you change the inputs — the finite-element result reproduces classical beam theory to numerical precision.

What units does it use?

SI units: length in metres (m), point loads in kilonewtons (kN), distributed loads in kN/m and Young's modulus in gigapascals (GPa). Results are shown in kNm, kN and mm.

Does it include the beam's self-weight?

No. Only the loads you enter are applied, so you can match a hand calculation exactly. Add a distributed load equal to the self-weight if you want to include it.

Can I analyse continuous beams, 3D frames or Eurocode checks?

Yes — open the full FERS Cloud app for multi-span and continuous beams, 3D frames and trusses, load combinations and Eurocode EC3 steel checks. This page covers the single-span cases most people need quickly.

Need more than a single beam?

Open the full FERS Cloud app for continuous and multi-span beams, 2D and 3D frames and trusses, load combinations and Eurocode EC3 steel checks.